Determinant: Expansion via Linearity and Alternation | Generated by AI

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When you learn that the determinant is a function that is

  1. multilinear in the rows (or columns), and
  2. alternating (swapping two rows flips its sign),

the cofactor‐expansion formula falls out naturally. Here’s a step‐by‐step “why” for the 3×3 case:


1. Determinant via permutations

The most general definition of a 3×3 determinant is

\[\det A \;=\; \sum_{\sigma\in S_3}\!\mathrm{sgn}(\sigma)\,a_{1,\sigma(1)}\,a_{2,\sigma(2)}\,a_{3,\sigma(3)},\]

where you sum over all six permutations σ of {1,2,3}, and sgn(σ) is +1 for even permutations and –1 for odd ones.

If you write them out, you get exactly the six terms:

\[a_{11}a_{22}a_{33},\;a_{12}a_{23}a_{31},\;a_{13}a_{21}a_{32} \;-\; \bigl(a_{13}a_{22}a_{31}+a_{11}a_{23}a_{32}+a_{12}a_{21}a_{33}\bigr).\]

2. Grouping by one row or column

Notice you can group those six terms according to which entry in the first row they use:

That’s exactly the cofactor expansion along the first row:

\[\det A = a_{11}C_{11} \;+\; a_{12}C_{12} \;+\; a_{13}C_{13},\]

where each cofactor $C_{1j} = (-1)^{1+j}\det(\text{minor}_{1j})$.


3. Why “minors” and “signs”?

Because the determinant must be linear in each row, you can “pull out” one entry from a row, leaving the determinant of the smaller matrix multiplied by that entry. The alternating property forces those $(−1)$ signs.


4. Geometric intuition

For a 3×3 matrix whose rows are vectors $\mathbf{u},\mathbf{v},\mathbf{w}\in\mathbb{R}^3$, $\det A$ is the signed volume of the parallelepiped they span.


5. Generalization to $n\times n$

All of this works in the same way for any size $n$: the permutation definition has $n!$ terms, you group them by one row or column, and each group collapses to

\[a_{ij}\,(-1)^{i+j}\det(\text{minor}_{ij}).\]

That is the cofactor expansion principle.


In short: Cofactor expansion is simply the permutation‐sum definition of the determinant, reorganized by one row (or column), together with the requirements of linearity and sign‐alternation. It offers a recursive way to compute—and a clear geometric picture of—the determinant.


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