Scheme CPS Transform Code Breakdown | Generated by AI

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Here’s the code extracted from your screenshot, reformatted for clarity:

(define cps
  (lambda (exp)
    (letrec
        ([trivial? (lambda (x) (memq x '(zero? add1 sub1)))]
         [id (lambda (v) v)]
         [ctx0 (lambda (v) `(k ,v))]   ; tail context
         [fv (let ([n -1])
               (lambda ()
                 (set! n (+ 1 n))
                 (string->symbol (string-append "v" (number->string n)))))]
         [cps1
          (lambda (exp ctx)
            (pmatch exp
              [,x (guard (not (pair? x))) (ctx x)]
              [(if ,test ,conseq ,alt)
               (cps1 test
                     (lambda (t)
                       (cond
                         [(memq ctx (list ctx0 id))
                          `(if ,t ,(cps1 conseq ctx) ,(cps1 alt ctx))]
                         [else
                          (let ([u (fv)])
                            `(let ([k (lambda (,u) ,(ctx u))])
                               (if ,t ,(cps1 conseq ctx0) ,(cps1 alt ctx0))))])))]
              [(lambda (,x) ,body)
               (ctx `(lambda (,x ,k) ,(cps1 body ctx0)))]
              [(,op ,a ,b)
               (cps1 a
                     (lambda (v1)
                       (cps1 b
                             (lambda (v2)
                               (ctx `(,op ,v1 ,v2)))))))]
              [(,rator ,rand)
               (cps1 rator
                     (lambda (r)
                       (cps1 rand
                             (lambda (d)
                               (cond
                                 [(trivial? r) (ctx `(,r ,d))]
                                 [(eq? ctx ctx0) `(,r ,d ,k)] ; tail call
                                 [else
                                  (let ([u (fv)])
                                    `(,r ,d (lambda (,u) ,(ctx u))))]))))))]))]
      (cps1 exp id))))

What This Code Does

This is an implementation of a Continuation-Passing Style (CPS) transformer for a small Scheme-like language. CPS is a way of rewriting programs so that control flow is made explicit by passing continuation functions around.

Key Components

  1. Trivial operations

    (trivial? (lambda (x) (memq x '(zero? add1 sub1))))
    

    Marks some primitive operators as trivial (don’t need CPS wrapping).

  2. Continuation contexts

    [id (lambda (v) v)]      ; identity context
    [ctx0 (lambda (v) `(k ,v))] ; default tail continuation
    

    id just returns its argument, while ctx0 means “return value to continuation k”.

  3. Fresh variables

    [fv ...] ; generates symbols v0, v1, v2, ...
    

    Used when new bindings are needed.

  4. Main transformer

    cps1
    

    This recursively transforms expressions into CPS form, case by case.

    • Variables and constants If x is not a pair (atomic), just apply the continuation context.

    • Conditionals

      (if test conseq alt)
      

      Test is CPS-transformed first. If context is simple (ctx0 or id), produce a direct if. Otherwise, generate a new continuation k and CPS both branches with ctx0.

    • Lambdas

      (lambda (x) body)
      

      Transformed into (lambda (x k) <CPS of body>), i.e. lambdas now explicitly take a continuation.

    • Binary operations

      (op a b)
      

      Both operands are CPS’d, then combined.

    • Function application

      (rator rand)
      

      The operator and operand are CPS’d. Then depending on triviality:

      • If the operator is primitive, apply directly.
      • If in tail position (ctx = ctx0), just call (r d k).
      • Otherwise, wrap in a new continuation.
  5. Entry point

    (cps exp)
    

    Calls cps1 with id as the initial context.


Example Intuition

Suppose you CPS this:

((lambda (x) (add1 x)) 5)

The CPS transform will turn it into something like:

((lambda (x k)
   (k (add1 x)))
 5
 k)

Where k is the continuation for the result. Instead of returning a value, the function calls k with it.


Review


✅ Overall: This is a neat educational implementation of CPS conversion for a toy Scheme. It clearly demonstrates the mechanics of continuation passing: adding k arguments, wrapping branches, and making control explicit.


Would you like me to walk through a concrete worked example (e.g., show step-by-step CPS transformation of (if (zero? x) (add1 y) (sub1 y)))? That way you can see exactly how this code rewrites it.


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